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Complex numbers

Until now we have used real numbers. We will turn our attention to complex numbers and use them to understand different concepts. A complex number can be considered as an extension of real numbers. A complex number has real and imaginary part and is represented as: $$ c = a + ib, \quad i = \sqrt{-1} $$

Complex Plane

We can represent the complex number \(a + ib\) in a two dimensional plane as follows:

  • Real value \(a\) is represented in \(x\)-axis.
  • Imaginary value \(b\) in \(y\)-axis.

This is called the complex plane, also called the Argand plane. Every complex number can therefore be associated with a point in the complex plane. In this case: $$ a + ib \equiv (a, b) $$ For example, the point \((3, 2)\) is the complex number \(3 + 2i\) which can be represented as:

Note that all real numbers can also be considered as complex numbers with \(b=0\), thereby all real numbers fall on the \(x\)-axis. The length of a complex number \((a, b)\) can be considered as the length of the line joining the origin and the complex number: $$ ||x||^2=a^2+b^2 $$ Complex number can also be represented using the angle \(\theta\) with respect to positive \(x\)-axis and length \(r\). $$ c=re^{i\theta}=r({cos\theta + i sin\theta}) $$ Graphically, we can represent this as follows:

Properties

Some basic operations and properties on complex numbers.

Addition

If \(c_1= a_1+ib_1\) and \(c_2=a_2+ib_2\), then: $$ c_1+c_2= (a_1+a_2)+i(b_1+b_2) $$

Multiplication

Multiplication of complex numbers works just like multiplication of real numbers, just note that \(i=\sqrt{-1}\) and do multiplication using distributive property. Then: $$ \begin{aligned} c_1 c_2 &= (a_1+ib_1)(a_2+ib_2)\\ &= (a_1a_2-b_1b_2) +i(a_1b_2+a_2b_1) \end{aligned} $$

Complex conjugate

The complex conjugate of \(c = a + ib\) is given by: $$ \bar{c} = a - ib $$ We have the following property: $$ \begin{aligned} c \bar{c} &= (a + ib)(a - ib)\\ &= a^2 + b^2\\ &= ||c||^2 \end{aligned} $$

If we look at it in another way: $$ \begin{aligned} \bar{c} &= r(\cos \theta - i \sin \theta)\\ &= re^{-i\theta} \end{aligned} $$