PPA-2

Question

Accept a sequence of words as input, append all these words to a list in the order in which they are entered, and print this list as output. The first line in the input is a positive integer \(n\) that denotes the number of words in the sequence. The next \(n\) lines will have one word on each line.

Hint

There are two steps here:

• accept a string during each iteration of the loop
• append this string to a list

The easiest thing would be a for loop as the number of iterations is known to us (first line of the input). But what if we go for a while loop?

while n > 0:
    ### accept string as input ###
    ### append string to list ###
    n -= 1

Do you think the above code works?

Solution

Solution-1

Notice that the loop variable i is not being used anywhere within the body of the loop. It just acts as a syntactic placeholder. Head to solution-2 to see what could be done in such cases.

n = int(input())
L = [ ]
for i in range(n):
    word = input()
    L.append(word)
print(L)

Solution-2

When the loop variable is just a dummy placeholder, coders often use an _ instead of a variable name such as i or j. Check out this Stackoverflow answer for more details.

n = int(input())
L = [ ]
for _ in range(n):
    word = input()
    L.append(word)
print(L)

Video Solution